x^2+9x-486=0

Solution for x^2+9x-486=0 equation:

x^2+9x-486=0

a = 1; b = 9; c = -486;
Δ = b2-4ac
Δ = 92-4·1·(-486)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-45}{2*1}=\frac{-54}{2}
=-27
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+45}{2*1}=\frac{36}{2}
=18
$